13 (CIE 2015, s, paper 22, question 6)
(a) Solve 6x−2=14. [2]
(b) Solve loga2y2+loga8+loga16y−loga64y=2loga4 [4]
14 (CIE 2015,w, paper 13, question 12 )
(a) Given that 22x−1×4x+y=128 and d92y−x27y−4=1, find the value of each of the integers x and y. [4]
(b) Solve 2(5)2z+5z−1=0. [4]
15 (CIE 2016, march, paper 12, question 2)
Given that p−2qr−12√p13q2r−3=paqbrc, find the values of a,b and c. [3]
16 (CIE 2016, s, paper 11, question 2)
(a) Solve the equation 163x−1=8x+2. [3]
(b) Given that (a13b−12)3a−23b12=apbq, find the value of each of the constants p and q. [2]
17 (CIE 2016,w, paper 11, question 2)
Given that p13q−12r12p−23√(qr)5=paqbrc, find the value of each of the integers a,b and c.
18 (CIE 2016,w, paper 13 , question 2)
Express 4m√m−9√m2√m+3√m in the form Am+B, where A and B are integers to be found. [3]
19 (CIE 2016,w, paper 23 , question 2) Solve the equation e3x=6ex.
20 (CIE 2017, s, paper 11, question 3)
(a) Simplify √x8y10÷3√x3y−6, giving your answer in the form xayb, where a and b are integers. [2]
(b) (i) Show that 4(t−2)12+5(t−2)32 can be written in the form (t−2)p(qt+r), where p,q and 1 are constants to be found.
(ii) Hence solve the equation 4(t−2)12+5(t−2)32=0. [1]
21 (CIE 2017, s, paper 23, question 1)
(a) Solve the equation 72x+5=2.5, giving your answer correct to 2 decimal places. [3]
(b) Express (5√q)3(625p12q)14 in the form 5apbqc, where a,b and c are constants. [3]
22 (CIE 2017,w, paper 11 , question 3
(a) Given that T=2πl12g−12, express l in terms of T,g and π. [2]
(b) By using the substitution y=x13, or otherwise, solve x23−4x3+3=0. [4]
23 (CIE 2017,w, paper 22 , question 2)
Solve the equation 2x1.5+6x−0.5x0.5+5x−0.5=x. 24 (CIE 2018, s, paper 12 , question 12)
Do not use a calculator in this question.
(a) Given that 6p×8p+2×3q92q−3 is equal to 27×34, find the value of each of the constants p and q. [3]
(b) Using the substitution u=x13, or otherwise, solve 4x13+x23+3=0. [4]
Answers
13. (a) 1.226, (b) 2
14. (a) x=4,y=−4
(b) z=−0.431
15. a=−13/6,b=0,c=1
16. (a) 10/9
(b) 5/3,−2
17. a=1,b=−3,c=−1
18. 2m−3
19. x=.5ln6
20. (a) x3y7
(bi) (t−2)1/2(5t−6)
(bii) 2,65
21. (a) −2.26
(b) 52p−3q5/4
22. (a) l=T2g4π2
(b) x=1,x=27
23. x=3,2
24. (a) p=1/4,q=3/4
(b) x=−1,x=−27
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