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Simple Rational Function

Proof : ax+bcx+d is one to one correspondence
$ \displaystyle f(x)=ax+bcx+df is one to one f(x)=f(y)x=y Assume that f(x)=f(y),thenax+bcx+d=ay+bcy+dacxy+adx+bcy+bd=acxy+bcx+ady+bdadx+bcy=bcx+adyadxbcx=adybcy(adbc)x=(adbc)y x=y (adbc)Hence f is one to one.$

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